CS302 spring 2012
Assignment No. 4
Due Date:
Your assignment must be
uploaded/submitted before or on 25th June, 2012.
Total Marks: 20
Rules for Marking:
It should be clear that your assignment will not get any
credit if:
The
assignment is submitted after due date.
The
submitted assignment file is corrupted.
The assignment is copied.
The assignment material is directly copied from internet.
Objective:
The objective of this assignment is
to prepare students to familiar with making next state table for Moore’s
machine and designing 4 bit up and down counters using D flip flops.
Q1 Marks
6
State diagram of a Moore machine is given below; draw the
next state table of this Moore machine (starting from state 101).
Solution:
Present State
|
Next State
|
||||
Q2
|
Q1
|
Q0
|
Q2
|
Q1
|
Q0
|
1
|
0
|
1
|
1
|
0
|
0
|
1
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
1
|
0
|
1
|
0
|
0
|
1
|
0
|
1
|
0
|
1
|
Q2 Marks 7 + 7 = 14
Give the input tables for both 4 bit up counter and 4 bit
down counter consisting of D type flip flops.
Solution:
Present State
|
Next State
|
D Flip Flop Input
|
|||||||||
Q3
|
Q2
|
Q1
|
Q0
|
Q3
|
Q2
|
Q1
|
Q0
|
D3
|
D2
|
D1
|
D0
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
1
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
1
|
1
|
1
|
1
|
1
|
1
|
1
|
1
|
1
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
D Flip Flop input
table for 4 bit up counter
Present State
|
Next State
|
D Flip Flop Input
|
|||||||||
Q3
|
Q2
|
Q1
|
Q0
|
Q3
|
Q2
|
Q1
|
Q0
|
D3
|
D2
|
D1
|
D0
|
0
|
0
|
0
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
1
|
1
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
1
|
0
|
0
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
1
|
1
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
0
|
0
|
1
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
0
|
0
|
1
|
0
|
0
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
0
|
1
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
1
|
1
|
1
|
0
|
0
|
1
|
1
|
0
|
0
|
1
|
1
|
1
|
0
|
1
|
1
|
1
|
1
|
1
|
1
|
1
|
1
|
D
Flip Flop input table for 4 bit down counter
0 comments:
Post a Comment